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<html><body><h2 id="content-id-9348162750-2"><b>Driver 2 Questions Overview</b></h2><p>Driver 2 Questions have a good weightage in the Ssc Chsl Exam and the type of question asked in Ssc Chsl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Driver 2 Questions.</p><h2 id="content-id-5821073496-3"><b>Question On Driver 2 </b></h2>If the speed of light in a medium is 2.25 x 108 m/s,  its refractive index is ________.
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Easy </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 31 Seconds </h3></div></div><h2 id="content-id-4093168572-4"><b> Driver 2 Questions Options</b></h2><ol><li><p>0.75</p>
</li><li><p>1.33</p>
</li><li><p>1.75</p>
</li><li><p>1.50</p>
</li></ol> <h2 id="content-id-0738546921-5"><b> Driver 2 Questions Solution</b></h2><p>The correct answer is <strong>option 2</strong> i.e. <strong>1.33.</strong></p>

<p>The value 1.33 is determined using the absolute refractive index formula, $n = \frac{c}{v}$. In this equation, $c$ represents the constant speed of light in a vacuum ($3 \times 10^8\text{ m/s}$), and $v$ represents the speed of light inside the given medium ($2.25 \times 10^8\text{ m/s}$). Dividing these numerical values gives $n = \frac{3 \times 10^8}{2.25 \times 10^8} = 1.33$. This optical property is a completely dimensionless quantity that mathematically demonstrates how much the speed of a light wave is reduced when it propagates through this medium.</p>
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The correct answer is option 2 i.e. 1.33 - Driver 2 Questions are asked in Ssc Chsl exams and your question has been explained by experts like Neetu Mam.

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