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<html><body><h2 id="content-id-1925746038-2"><b>Physics Questions Overview</b></h2><p>Physics Questions have a good weightage in the Ssc Chsl Exam and the type of question asked in Ssc Chsl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Physics Questions.</p><h2 id="content-id-3827016945-3"><b>Question On Physics </b></h2>An object is subjected to a force of 30 N acting towards the right and a frictional force of 30 N acting towards the left. What is the resultant state of the object? 
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Easy </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 34 Seconds </h3></div></div><h2 id="content-id-1659480237-4"><b> Physics Questions Options</b></h2><ol><li><p>It will accelerate to the right.</p>
</li><li><p>It will accelerate to the left.</p>
</li><li><p>The body will remain at rest (equilibrium).</p>
</li><li><p>It will oscillate in place.</p>
</li></ol> <h2 id="content-id-8716492530-5"><b> Physics Questions Solution</b></h2><p>The correct answer is <strong>option 3 </strong>i.e. <strong>The body will remain at rest (equilibrium).</strong></p>



<p>The two forces acting on the object are equal in magnitude (<strong>30 N</strong>) but opposite in direction. When you add them together, they completely cancel each other out, resulting in a net (resultant) force of 0 N.</p>

<p>According to <strong>Newton's First Law of Motion</strong>, an object will maintain its current state of motion unless acted upon by a non-zero net force. Because the net force is zero, the object is in a state of <strong>translational equilibrium</strong>.</p>

<ul>
	<li>
	<p>If the object was originally at rest, it will remain at rest.</p>
	</li>
	<li>
	<p>If it was already moving, it would continue to move at a constant velocity in a straight line (no acceleration). Given the typical context of multiple-choice questions like this, "remain at rest (equilibrium)" is the correct choice.</p>
	</li>
</ul>
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