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Hello everyone, simplification is a topic that is asked in the quantitative aptitude section of almost every competitive exam. To score good marks you need to excel in this topic, so here are some key concepts which will let you learn about it more clearly.

Here, we are going to learn all about the BODMAS rule, what it is, where to use it along with some mind-blowing formulae which will transform you into human calculator.

E.g. 221 ÷ 13 × √576 + (10)2 = ?

We are completely clueless about where to start right now, so let’s start from left

⇒ 221 ÷ 13 × 24 + 100 = ? ⇒ 221 ÷13 × 124 = ?

⇒ 221 ÷ 1612 = ? ⇒ 7.290 (Approx.)

Which is wrong, so how to approach these types of questions? Is there a specific method to approach them?

Yes, VBODMAS rule.

<h2>VBODMAS Rule</h2>

Full form of VBODMAS is:

<table cellspacing="0" style="width:300px">
	<tbody>
		<tr>
			<td>
			Sr. No.
			</td>
			<td>
			Alphabet
			</td>
			<td>
			Significance
			</td>
		</tr>
		<tr>
			<td>
			1.
			</td>
			<td>
			V
			</td>
			<td>
			Vinculum or Bar
			</td>
		</tr>
		<tr>
			<td>
			2.
			</td>
			<td>
			B
			</td>
			<td>
			Brackets
			</td>
		</tr>
		<tr>
			<td>
			3.
			</td>
			<td>
			O
			</td>
			<td>
			Of
			</td>
		</tr>
		<tr>
			<td>
			4.
			</td>
			<td>
			D
			</td>
			<td>
			Division
			</td>
		</tr>
		<tr>
			<td>
			5.
			</td>
			<td>
			M
			</td>
			<td>
			Multiplication
			</td>
		</tr>
		<tr>
			<td>
			6.
			</td>
			<td>
			A
			</td>
			<td>
			Addition
			</td>
		</tr>
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			<td>
			7.
			</td>
			<td>
			S
			</td>
			<td>
			Subtraction
			</td>
		</tr>
	</tbody>
</table>

For every question we have to do each step from up to bottom. Let’s take an example and try to solve it.

E.g. 221 ÷ 13 × √576 + (10)2 = ?

Step-1: First try to Solve √576 and (10)2

⇒ 221 ÷ 13 × 24 + 100 = ?

Step-2: Division

⇒ 221 ÷ 13 × 24 + 100 = ?

⇒ 17 × 24 + 100 = ?

Step-3: Multiplication

⇒ 17 × 24 + 100 = ? ⇒ 408 + 100 = ?

Step-4: Addition

 408 + 100 = ? ⇒ 508 (Ans.)

Tip: “While solving the brackets in any question, first we solve the small brackets (), then we solve the curly brackets

{} and at last we solve the big brackets [].”

E.g. [(2211 ÷ 67)2 – 21 × √(256 )] ÷ (549 – 213) = ? ÷ 1344

Let’s apply VBODMAS rule here

Step-1: Let’s Solve √256

⇒ [(2211 ÷ 67)2 - 21 × 16] ÷ (549 - 213) = ? ÷ 1344

Step-2: Start opening the Brackets

⇒ [(2211 ÷ 67)2 - 21 × 16] ÷ (549 – 213) = ? ÷ 1344

⇒ [(33)2 – 21 × 16] ÷ 336 = ? ÷ 1344

Step-3: Now we have to first simplify equation in bracket then open it by VBODMAS

⇒ [1089 – 21 × 16] ÷ 336 = ? ÷ 1344

⇒ [1089 – 336] ÷ 336 = ? ÷ 1344

Step-4: Now open the bracket

⇒ [1089 –336] ÷ 336 = ? ÷ 1344

⇒ 753 ÷ 336 = ? ÷ 1344

<h3>Step-5: Division</h3>

⇒ 753 ÷ 336 = ? ÷ 1344

⇒ 753 × 1344 ÷ 336 = ?

⇒ ? = 753 × 4 = 3012 (Ans.)

E.g. 1/6 of 355 of 1/5 of 2160 + √3969 - 448.98 = ?

Step-1: As there are no brackets, so we first solve of

1/5 of 2160 ⇒ 1/5 × 2160 ⇒ 432

And 1/6 of 355 ⇒ 355/6 So, we got,

⇒ 355/6 of 432 + 37 – 448.98

⇒ 355/6 of 432 + 37 – 448.98

⇒ 355/6 × 432 + 37 – 448.98

Step-2: Division

⇒ 355 × 72 + 37 – 448.98

Step-3: Multiplication

⇒ 355 × 72 + 37 – 448.98 ⇒ 25560 + 37 – 448.98

Step-4: Addition

⇒ 25560 + 37 – 448.98

⇒ 25597 – 448.98

Step-5: Subtraction

⇒ 25597 – 448.98 = 25,148.02 (Ans.)

E.g. 28/9 ×144/12 ÷ 17/5 + 13/17

Step-1: By BODMAS rule we would firstly (D) Divide

⇒ 28/9 × 12 ÷ 17/5 + 13/17

⇒ 28/9 × 60/17 + 13/17

Step-2: Multiplication

⇒ 28/9 × 60/17 + 13/17

⇒ 560/51 + 13/17

Step-3 Addition

⇒ (560 + 39)/51 = 599/51 (Ans.)

So here it concludes our blog. Hope you have a learnt a lot and the next thing to excel in it, is to pratice more and more. So practice and all the best!

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