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<html><body><h2 id="content-id-5842617390-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the SSC CHSL English Exam and the type of question asked in SSC CHSL English exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-3745680219-3"><b>Question On Trigonometry </b></h2>What is the value of the given expression? (rac{sin^4 A- cos^4A+1}{1+ rac{1}{tan^2A}}) 
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Easy </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 31 Seconds </h3></div></div><h2 id="content-id-4175283069-4"><b> Trigonometry Questions Options</b></h2><ol><li><p><span class="math-tex">\(2 sin^2 A + tan ^2 A\)</span></p>
</li><li><p><span class="math-tex">\(2 sin A . cos A\)</span></p>
</li><li><p><span class="math-tex">\(\frac{sin A.cos A}{tan^2A}\)</span></p>
</li><li><p><span class="math-tex">\(2 sin^4 A\)</span></p>
</li></ol> <h2 id="content-id-1498753062-5"><b> Trigonometry Questions Solution</b></h2><p>The correct answer is <strong>Option 4</strong> i.e. <strong>â&#128;&#139;â&#128;&#139;</strong><span class="math-tex">\(2 sin^4 A\)</span>.</p>

<p><span class="math-tex">\(\frac{sin^4 A- cos^4A+1}{1+ \frac{1}{tan^2A}}\)</span></p>

<p>⇒ <span class="math-tex">\(\frac{(sin^2 A)^2- (cos^2A)^2+1}{1+ cot^2A}\)</span></p>

<p>⇒ <span class="math-tex">\(\frac{(sin^2 A- cos^2A)(sin^2 A+ cos^2A)+1}{cosec^2A}\)</span></p>

<p>⇒ <span class="math-tex">\(\frac{(sin^2 A- cos^2A)+1}{cosec^2A}\)</span></p>

<p>⇒ <span class="math-tex">\(\frac{(sin^2 A- cos^2A)+(sin^2 A+ cos^2A)}{cosec^2A}\)</span></p>

<p>⇒ <span class="math-tex">\(\frac{2sin^2A}{cosec^2A}\)</span> = 2sin<sup>2</sup>A × sin<sup>2</sup>A = 2sin<sup>4</sup>A</p>
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