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<html><body><h2 id="content-id-1702835469-2"><b>Caselets Questions Overview</b></h2><p>Caselets Questions have a good weightage in the Ssc Chsl Exam and the type of question asked in Ssc Chsl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Caselets Questions.</p><h2 id="content-id-7619245803-3"><b> Comprehension On Caselets Questions</b></h2>Direction: Read the following information carefully and answer the questions that follow.

A local bakery prepares five distinct varieties of items represented as P, Q, R, S, and T. Variety S constitutes 15% of the overall total items produced across all five categories. The number of items of variety T produced is 40 more than the number of items of variety S produced, and the total number of items of variety R produced is 80 more than variety T. The ratio of the total number of items of variety P to variety R produced is 3 : 4, and the total number of items of variety Q produced is 100. Regarding item specifications, 60% of items of variety P are eggless, whereas 40% of items of variety R are eggless. Across all five categories combined, the total number of non-eggless (containing egg) items produced is 380. Furthermore, the total number of eggless items of variety Q produced is equal to the total number of non-eggless items of variety S produced. For variety T, the ratio of eggless to non-eggless items produced is 3 : 2. Lastly, the number of eggless items of variety S produced is double the number of non-eggless items of variety S.
<h2 id="content-id-1986532074-4"><b>Question On Caselets </b></h2>What is the ratio of the total number of eggless items of varieties P and Q together to the total number of non-eggless items of varieties R and S together?
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Easy </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 86 Seconds </h3></div></div><h2 id="content-id-2847690351-5"><b> Caselets Questions Options</b></h2><ol><li><p>37 : 46</p>
</li><li><p>47 : 36</p>
</li><li><p>37 : 35</p>
</li><li><p>39 : 49</p>
</li><li><p>None of these</p>
</li></ol> <h2 id="content-id-1079825364-6"><b> Caselets Questions Solution</b></h2><p>The correct answer is <strong>option 1</strong> i.e. <strong>37 : 46</strong>.</p>

<p>Let the total number of items produced across all five varieties be x.</p>

<p>S = 15% of x</p>

<p><span class="math-tex">\(S = \frac{15}{100}x = \frac{3x}{20}\)</span></p>

<p>T = S + 40</p>

<p>R = T + 80 = S + 120</p>

<p>Also, P : R = 3 : 4</p>

<p><span class="math-tex">\(P = \frac{3}{4}R = \frac{3}{4}(S+120)\)</span></p>

<p>Q = 100</p>

<p>Since the total number of items is x,</p>

<p><span class="math-tex">\(P + Q + R + S + T = x\)</span></p>

<p>Substituting the values in terms of S:</p>

<p><span class="math-tex">\(\frac{3}{4}(S+120) + 100 + (S+120) + S + (S+40) = x\)</span></p>

<p>Since S = 15% of x, <span class="math-tex">\(S = \frac{3x}{20}\)</span></p>

<p>On solving, x = 800.</p>

<table border="1" cellpadding="6" cellspacing="0" style="border-collapse:collapse; text-align:center; width:300px">
	<thead>
		<tr>
			<th>Variety</th>
			<th>Total Items</th>
			<th>Eggless Items</th>
			<th>Non-eggless Items</th>
		</tr>
	</thead>
	<tbody>
		<tr>
			<td>P</td>
			<td>180</td>
			<td>108</td>
			<td>72</td>
		</tr>
		<tr>
			<td>Q</td>
			<td>100</td>
			<td>40</td>
			<td>60</td>
		</tr>
		<tr>
			<td>R</td>
			<td>240</td>
			<td>96</td>
			<td>144</td>
		</tr>
		<tr>
			<td>S</td>
			<td>120</td>
			<td>80</td>
			<td>40</td>
		</tr>
		<tr>
			<td>T</td>
			<td>160</td>
			<td>96</td>
			<td>64</td>
		</tr>
		<tr>
			<td><strong>Total</strong></td>
			<td><strong>800</strong></td>
			<td><strong>420</strong></td>
			<td><strong>380</strong></td>
		</tr>
	</tbody>
</table>

<p>Now, the number of eggless items of P and Q together = P + Q = 108 + 40 = 148</p>

<p>The number of non-eggless items of R and S together = R + S = 144 + 40 = 184</p>

<p>Required ratio = 148 : 184 <span class="math-tex">\(= 37 : 46\)</span></p>


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