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<html><body><h2 id="content-id-1289370465-2"><b>Geometry Questions Overview</b></h2><p>Geometry Questions have a good weightage in the Ssc Chsl Exam and the type of question asked in Ssc Chsl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Geometry Questions.</p><h2 id="content-id-4291608573-3"><b>Question On Geometry </b></h2>What is the length of the altitude (in cm) to the side QR of a triangle PQR with side PQ = 25 cm, PR = 25 cm and QR = 40 cm?
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Easy </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 33 Seconds </h3></div></div><h2 id="content-id-6058719423-4"><b> Geometry Questions Options</b></h2><ol><li><p>15</p>
</li><li><p>18</p>
</li><li><p>27</p>
</li><li><p>24</p>
</li></ol> <h2 id="content-id-9671835402-5"><b> Geometry Questions Solution</b></h2><p>The correct answer is <strong>option 1</strong> i.e. <strong>15. </strong></p>

<p>Since PQ = PR = 25 cm, triangle PQR is isosceles with base QR = 40 cm.</p>

<p>Altitude from P to QR will bisect QR:</p>

<p>So, each half = 20 cm</p>

<p>Now using Pythagoras: </p>

<p>Altitude h satisfies:</p>

<p>⇒  h<sup>2</sup> + 20<sup>2</sup>  = 25<sup>2</sup> </p>

<p>⇒   h<sup>2</sup>  + 400 = 625</p>

<p>⇒   h<sup>2</sup> = 225</p>

<p>⇒   h = 15 cm</p>
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The correct answer is option 1 i.e. 15.? - Geometry Questions are asked in Ssc Chsl exams and your question has been explained by experts like Neetu Mam.

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