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<html><body><h2 id="content-id-0318756294-2"><b>Problem On Trains Questions Overview</b></h2><p>Problem On Trains Questions have a good weightage in the Ssc Chsl Exam and the type of question asked in Ssc Chsl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Problem On Trains Questions.</p><h2 id="content-id-3451968720-3"><b>Question On Problem On Trains </b></h2>Train A and Train B are traveling in the same direction on parallel tracks. Length of Train A is 280 meters and its speed is X km/h. Length of Train B is L meters and its speed is (X − 15) km/h. Train A crosses Train B completely in 144 seconds. If they were traveling in opposite directions, they would cross each other in 16 seconds.

Match the numeric value of colum I and Column II.


	
		
			Column I
			Column II
		
	
	
		
			(A) A car covers a distance equal to the combined length of Train A and Train B. If the car travels the first half of this distance at 40 km/h and the second half at 60 km/h, find the total time taken (in hours) to cover the entire distance.
			(P) A two-digit number is such that the sum of its digits is 8 and the tens digit exceeds the units digit by 2. The number obtained is _____.
		
		
			(B) A platform has a length which is 60 meters more than the combined length of Train A and Train B. If a new train, Train C, crosses this platform at a speed of 72 km/h and the length of the train C is 25% more than to the train B, the time taken (in seconds) by Train C to cross the platform _____
			(Q) When 40 is added to the numerator of a fraction, its value becomes 80. When 2 is added to its denominator, its value becomes 40. Find the value of the fraction.
		
		
			(C) A car travels from town P to town Q at the speed of Train B and returns from town Q to town P at the speed of Train A (in km/h). Find the average speed of the car (in km/h) for the entire journey.
			(R) The smallest value of 80x2 − 81x + 1 = 0
			 
			
		
	



<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Easy </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 107 Seconds </h3></div></div><h2 id="content-id-3861795240-4"><b> Problem On Trains Questions Options</b></h2><ol><li><p>B – P, and C – R</p>
</li><li><p>Only A – R, C – Q</p>
</li><li><p>A – R, B – P, and C – Q</p>
</li><li><p>Only A – R, B – P</p>
</li><li><p>A – Q, B – P, and C – R</p>
</li></ol> <h2 id="content-id-5789431062-5"><b> Problem On Trains Questions Solution</b></h2><p>The correct answer is <strong>option 3</strong> i.e. <strong>A – R, B – P, and C – Q</strong>.</p>

<p>Length of Train A = 280 m</p>

<p>Let length of Train B = L m</p>

<p>Relative speed in same direction = 15 km/h = 15 × 5/18 = 25/6 m/s</p>

<p>Total length = 144 × 25/6 = 600 m</p>

<p>L = 600 − 280 = 320 m</p>

<p>Speed sum in opposite direction = 600/16 = 37.5 m/s = 37.5 × 18/5 = 135 km/h</p>

<p>X + (X − 15) = 135</p>

<p>2X = 150</p>

<p>X = 75 km/h</p>

<p>Speed of Train B = 75 − 15 = 60 km/h</p>

<p>(A)</p>

<p>Distance = 280 + 320 = 600 m = 0.6 km</p>

<p>Average speed = 2 × 40 × 60/(40 + 60) = 48 km/h</p>

<p>Time = 0.6/48 = 1/80 hour</p>

<p>(B)</p>

<p>Platform length = 600 + 60 = 660 m</p>

<p>Length of Train C = 320 × 125/100 = 400 m</p>

<p>Speed of Train C = 72 km/h = 20 m/s</p>

<p>Time = (660 + 400)/20 = 53 seconds</p>

<p>(C)</p>

<p>Average speed = 2 × 60 × 75/(60 + 75) = 200/3 km/h</p>

<p>(P)</p>

<p>Let tens digit = x</p>

<p>Units digit = y</p>

<p>x + y = 8</p>

<p>x − y = 2</p>

<p>2x = 10</p>

<p>x = 5</p>

<p>y = 3</p>

<p>Number = 53</p>

<p>(Q)</p>

<p>(n + 40)/d = 80</p>

<p>n + 40 = 80d</p>

<p>n = 80d − 40</p>

<p>n/(d + 2) = 40</p>

<p>80d − 40 = 40(d + 2)</p>

<p>40d = 120</p>

<p>d = 3</p>

<p>n = 200</p>

<p>Fraction = 200/3</p>

<p>(R)</p>

<p>80x<sup>2</sup> − 81x + 1 = 0</p>

<p>80x<sup>2</sup> − 80x − x + 1 = 0</p>

<p>(80x − 1)(x − 1) = 0</p>

<p>x = 1/80 or 1</p>

<p>Smallest value = 1/80</p>

<p>So, </p>

<p>A – R, B – P, and C – Q</p>
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