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<html><body><h2 id="content-id-1938467250-2"><b>Mensuration 3D Questions Overview</b></h2><p>Mensuration 3D Questions have a good weightage in the Ssc Chsl Exam and the type of question asked in Ssc Chsl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Mensuration 3D Questions.</p><h2 id="content-id-5703986124-3"><b>Question On Mensuration 3D </b></h2>The ratio of the total volume of a solid sphere to the total volume of a solid hemisphere is 16 : 1. The radius of the sphere is (x + 21) cm and the radius of the hemisphere is x cm. Both these solid shapes are melted and recast together to form a large single right circular solid cylinder. The height of this recast cylinder is 42 cm, and its base radius is ______cm. The amount of metal left over after casting both the sphere and the hemisphere to reach the cylinder's total volume capacity is 6,01,524 cm³. The curved surface area of the sphere is ______ cm2. (Take π = 22/7)
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Easy </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 56 Seconds </h3></div></div><h2 id="content-id-3401682957-4"><b> Mensuration 3D Questions Options</b></h2><ol><li><p>84, 22167</p>
</li><li><p>74, 22076</p>
</li><li><p>84, 22176</p>
</li><li><p>42, 22176</p>
</li><li><p>42, 12176</p>
</li></ol> <h2 id="content-id-9684502731-5"><b> Mensuration 3D Questions Solution</b></h2><p>The correct answer is <strong>option 3</strong> i.e. <strong>84, 22176.</strong></p>

<p>Volume of Sphere : Volume of Hemisphere = 16 : 1</p>

<p>Radius of Sphere = (x + 21) cm</p>

<p>Radius of Hemisphere = x cm</p>

<p>Height of Cylinder = 42 cm</p>

<p>Additional metal required = 601524 cm<sup>3</sup></p>

<p>[(4/3) × π × (x + 21)<sup>3</sup>] : [(2/3) × π × x<sup>3</sup>] = 16 : 1</p>



<p>2 × (x + 21)<sup>3</sup> : x<sup>3</sup> = 16 : 1</p>

<p>(x + 21)<sup>3</sup> : x<sup>3</sup> = 8 : 1</p>

<p>(x + 21) : x = 2 : 1</p>

<p>x + 21 = 2x</p>

<p>x = 21</p>

<p>Radius of Sphere = x + 21 = 42 cm</p>

<p>Radius of Hemisphere = x = 21 cm</p>

<p>Volume = (4/3) × (22/7) × 42<sup>3</sup> = 310464 cm<sup>3</sup></p>



<p>Volume = (2/3) × (22/7) × 21<sup>3</sup> = 19404 cm<sup>3</sup></p>



<p>Total Volume = 310464 + 19404 = 329868 cm<sup>3</sup></p>



<p>Volume of Cylinder = 329868 + 601524 = 931392 cm<sup>3</sup></p>



<p>πr<sup>2</sup>h = 931392</p>



<p>(22/7) × r<sup>2</sup> × 42 = 931392</p>

<p>132 × r<sup>2</sup> = 931392</p>

<p>r<sup>2</sup> = 931392 ÷ 132 = 7056</p>

<p>r = <strong>84 </strong>cm</p>

<p>Base radius of Cylinder = 84 cm</p>

<p>CSA of sphere= 4 × (22/7) × 42<sup>2</sup></p>



<p>= 4 × (22/7) × 1764</p>

<p>= <strong>22176 cm<sup>2</sup></strong></p>
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24 98 of 640 12 11 - Approximation Questions for Ssc Chsl

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The correct answer is option 3 i.e. 84,  - Mensuration 3D Questions are asked in Ssc Chsl exams and your question has been explained by experts like Neetu Mam.

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The ratio of the total vo - Mensuration 3D Questions for Ssc Chsl

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