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<html><body><h2 id="content-id-6341890572-2"><b>Quadratic Equation Questions Overview</b></h2><p>Quadratic Equation Questions have a good weightage in the Ssc Chsl Exam and the type of question asked in Ssc Chsl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Quadratic Equation Questions.</p><h2 id="content-id-8052643179-3"><b>Question On Quadratic Equation </b></h2>One root of the equation 2x2 - 8x - m = 0, is (rac{5}{2}). The other root of the equation and the value of m are respectively:
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Easy </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 34 Seconds </h3></div></div><h2 id="content-id-0893246715-4"><b> Quadratic Equation Questions Options</b></h2><ol><li><p><span class="math-tex">\(\frac{3}{2}\)</span> and -<span class="math-tex">\(\frac{15}{2}\)</span></p>
</li><li><p>-<span class="math-tex">\(\frac{3}{2}\)</span> and <span class="math-tex">\(\frac{15}{2}\)</span></p>
</li><li><p><span class="math-tex">\(\frac{5}{2}\)</span> and -<span class="math-tex">\(\frac{15}{2}\)</span></p>
</li><li><p>-<span class="math-tex">\(\frac{5}{2}\)</span> and <span class="math-tex">\(\frac{15}{2}\)</span></p>
</li></ol> <h2 id="content-id-4297168035-5"><b> Quadratic Equation Questions Solution</b></h2><p>The correct answer is <strong>Option 1</strong> i.e. <span class="math-tex">\(\frac{3}{2}\)</span> and -<span class="math-tex">\(\frac{15}{2}\)</span>.</p>

<p>2x<sup>2</sup> - 8x - m = 0</p>

<p>If <span class="math-tex">\(\frac{5}{2}\)</span> is the root of the equation</p>

<p>⇒ 2(<span class="math-tex">\(\frac{5}{2}\)</span>)<sup>2</sup> - 8 × <span class="math-tex">\(\frac{5}{2}\)</span> - m = 0</p>

<p>⇒ 2 × <span class="math-tex">\(\frac{25}{4}\)</span> - 20 - m = 0</p>

<p>⇒ <span class="math-tex">\(\frac{25}{2}\)</span> - 20 - m = 0</p>

<p>⇒ <span class="math-tex">\(\frac{25-40}{2}\)</span> - m = 0</p>

<p>⇒ <span class="math-tex">\(-\frac{15}{2}\)</span> - m = 0</p>

<p>⇒ m = <span class="math-tex">\(-\frac{15}{2}\)</span></p>

<p>Now, putting the value of m in the equation</p>

<p>⇒ 2x<sup>2</sup> - 8x - m = 0</p>

<p>⇒ 2x<sup>2</sup> - 8x - (<span class="math-tex">\(-\frac{15}{2}\)</span>) = 0</p>

<p>⇒ 2x<sup>2</sup> - 8x + <span class="math-tex">\(\frac{15}{2}\)</span> = 0</p>

<p>⇒ 4x<sup>2</sup> - 16x + 15 = 0</p>

<p>⇒ 4x<sup>2</sup> - 10x - 6x + 15 = 0</p>

<p>⇒ 2x(2x - 5) - 3(2x - 5) = 0</p>

<p>⇒ (2x - 3)(2x - 5)</p>

<p>x = <span class="math-tex">\(\frac{3}{2}\)</span>, <span class="math-tex">\(\frac{5}{2}\)</span> [<span class="math-tex">\(\frac{5}{2}\)</span> is already given]</p>

<p>Thus,</p>

<p>The root of the equation is <span class="math-tex">\(\frac{3}{2}\)</span> and the value of m is <span class="math-tex">\(-\frac{15}{2}\)</span></p>
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The correct answer is Option 1 i.e. (r - Quadratic Equation Questions are asked in Ssc Chsl exams and your question has been explained by experts like Neetu Mam.

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