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<html><body><h2 id="content-id-2089375614-2"><b>Geometry Questions Overview</b></h2><p>Geometry Questions have a good weightage in the Ssc Chsl Exam and the type of question asked in Ssc Chsl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Geometry Questions.</p><h2 id="content-id-3750962814-3"><b>Question On Geometry </b></h2>In an isosceles triangle ABC, AB = AC, and AD is perpendicular to BC. If AD = 5 cm and the perimeter of â&#150;³ABC is 50 cm, then twice the length of BC (in cm) is:
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Easy </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 34 Seconds </h3></div></div><h2 id="content-id-6805932174-4"><b> Geometry Questions Options</b></h2><ol><li><p>48</p>
</li><li><p>52</p>
</li><li><p>42</p>
</li><li><p>44</p>
</li></ol> <h2 id="content-id-4267513089-5"><b> Geometry Questions Solution</b></h2><p>The correct answer is <strong>option 1 </strong>i.e. <strong>48.</strong></p>

<p><strong><img loading="lazy" alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/Savita_(SSC%20Selection%C3%82%C2%A0Post%C3%82%C2%A0Quant)18-7-25))_D92025_07_19_12_54_55.png" style="height:180px; width:192px"></strong></p>

<p>Let BC = 2x</p>

<p>⇒ BD = DC = x</p>

<p>⇒ AD = 5 cm</p>

<p>In â&#150;³ABD</p>

<p>⇒ AB<sup>2</sup> = AD<sup>2</sup> + BD<sup>2</sup></p>

<p>⇒ AB = <span class="math-tex">\(\sqrt{5^2+x^2}\)</span> = <span class="math-tex">\(\sqrt{25+x^2}\)</span></p>

<p>⇒ AB + BC + CA = 50</p>

<p>⇒ 2AB + 2x = 50  [AB = AC]</p>

<p>⇒ 2<span class="math-tex">\(\sqrt{25+x^2}\)</span> + 2x = 50</p>

<p>⇒ <span class="math-tex">\(\sqrt{25+x^2}\)</span> + x = 25</p>

<p>⇒ <span class="math-tex">\(\sqrt{25+x^2}\)</span> = 25 - x</p>

<p>Squaring both sides</p>

<p>⇒ 25 + x<sup>2</sup> = (25 - x)<sup>2</sup></p>

<p>⇒ 25 + x<sup>2</sup> = 625 + x<sup>2</sup> - 50x</p>

<p>⇒ 50x = 600</p>

<p>⇒ x = 12</p>

<p>BC = 2x = 24 cm</p>

<p>Twice of BC = 24 × 2 = 48 cm</p>
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The correct answer is option 1 i.e. 4 - Geometry Questions are asked in Ssc Chsl exams and your question has been explained by experts like Neetu Mam.

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