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<html><body><h2 id="content-id-1634098752-2"><b>Average Questions Overview</b></h2><p>Average Questions have a good weightage in the Ssc Chsl Exam and the type of question asked in Ssc Chsl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Average Questions.</p><h2 id="content-id-8197420635-3"><b>Question On Average </b></h2>In a certain group of friends, the number of boys exceeds the number of girls by 10. The ratio of the number of boys to girls in this group is 3:2, and the average weight of all the friends is x kg. If the average weight of the girls is (x + 9) kg and the average weight of the boys is exactly 144 kg, calculate the value of the square root of (x + 19).
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Easy </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 44 Seconds </h3></div></div><h2 id="content-id-1489305267-4"><b> Average Questions Options</b></h2><ol><li><p>11</p>
</li><li><p>12</p>
</li><li><p>13</p>
</li><li><p>14</p>
</li><li><p>15</p>
</li></ol> <h2 id="content-id-9230761485-5"><b> Average Questions Solution</b></h2><p>The correct answer is <strong>option 3</strong> i.e. <strong>13</strong>.</p>

<p>Ratio of boys : girls = 3 : 2</p>

<p>Difference = 10</p>

<p>1 part = 10</p>

<p>Girls = 20</p>

<p>Boys = 30</p>

<p>Using weighted average,</p>

<p>50x = 30 × 144 + 20(x + 9)</p>

<p>50x = 4320 + 20x + 180</p>

<p>30x = 4500</p>

<p>x = 150</p>

<p>Required value</p>

<p>= √(x + 19)</p>

<p>= √169</p>

<p>= 13</p>
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The correct answer is option 3 i.e. 13. - Average Questions are asked in Ssc Chsl exams and your question has been explained by experts like Neetu Mam.

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