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<html><body><h2 id="content-id-0123846957-2"><b>Algebra Questions Overview</b></h2><p>Algebra Questions have a good weightage in the Ssc Chsl Exam and the type of question asked in Ssc Chsl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Algebra Questions.</p><h2 id="content-id-7392401658-3"><b>Question On Algebra </b></h2>If x is inversely proportional to y, and y = 6 when x = 4, find the value of x, when y = 32.
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Easy </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 31 Seconds </h3></div></div><h2 id="content-id-5764892031-4"><b> Algebra Questions Options</b></h2><ol><li><p><span class="math-tex">\(\frac 3 4\)</span></p>
</li><li><p><span class="math-tex">\(\frac{15}{13}\)</span></p>
</li><li><p><span class="math-tex">\(\frac{8}{13}\)</span></p>
</li><li><p><span class="math-tex">\(\frac{19}{12}\)</span></p>
</li></ol> <h2 id="content-id-9125638740-5"><b> Algebra Questions Solution</b></h2><p>The correct answer is <strong>option 1</strong> i.e. <span class="math-tex">\(\frac 3 4\)</span>.</p>

<p>Since x is inversely proportional to y,</p>

<p>xy = constant</p>

<p>x = 4 and y = 6</p>

<p>So, constant = 4 × 6 = 24</p>

<p>When y = 32,</p>

<p>⇒ x × 32 = 24</p>

<p>⇒ x = <span class="math-tex">\(24\over32\)</span> = <span class="math-tex">\(\frac 3 4\)</span></p>
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The correct answer is option 1 i.e. (r - Algebra Questions are asked in Ssc Chsl exams and your question has been explained by experts like Neetu Mam.

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