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<html><body><h2 id="content-id-6287459310-2"><b>Percentage Questions Overview</b></h2><p>Percentage Questions have a good weightage in the Ssc Cgl Exam and the type of question asked in Ssc Cgl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Percentage Questions.</p><h2 id="content-id-1753620894-3"><b>Question On Percentage </b></h2>If the radius of a sphere is increased by 40%, then find the percentage increase in its surface area.
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 31 Seconds </h3></div></div><h2 id="content-id-1632750948-4"><b> Percentage Questions Options</b></h2><ol><li><p>85%</p>
</li><li><p>88%</p>
</li><li><p>96%</p>
</li><li><p>92%</p>
</li></ol> <h2 id="content-id-7564981320-5"><b> Percentage Questions Solution</b></h2><p>The correct answer is <strong>Option 3</strong> i.e. <strong>96%.</strong></p>

<p>The radius of the sphere is increased by 40%</p>

<p>Let the old radius be R</p>

<p>Hence, the new radius is 1.4R</p>

<p>Surface area of sphere = 4πr<sup>2</sup></p>

<p>Let the old surface area be A</p>

<p>⇒ A = 4πR<sup>2</sup></p>

<p>New surface area A' = 4π( 1.4R × 1.4R )<sup>2</sup> = 1.96 × 4πR<sup>2</sup> = 1.96A</p>

<p>Hence percentage increase = <span class="math-tex">\(\frac{1.96 - 1}{1}\)</span> × 100 = 96%</p>
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Find the value of 221 2 - Simplification Questions for Ssc Cgl

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The correct answer is Option 3 i.e. 96% - Percentage Questions are asked in Ssc Cgl exams and your question has been explained by experts like Neetu Mam.

If the radius of a sphere - Percentage Questions for Ssc Cgl

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