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<html><body><h2 id="content-id-5264701389-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Ssc Chsl Exam and the type of question asked in Ssc Chsl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-8796314025-3"><b>Question On Trigonometry </b></h2>If tanθ = ({{sqrt{2y-2y^2}}over2y}) then, find the value of ({{sqrt{2y(y+1)}}} 	imes (sin	heta+cos	heta))
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 32 Seconds </h3></div></div><h2 id="content-id-4129683570-4"><b> Trigonometry Questions Options</b></h2><ol><li><p><span class="math-tex">\(5\sqrt3\over\sqrt5\)</span></p>
</li><li><p>3y</p>
</li><li><p><span class="math-tex">\( {{\sqrt{5y-3y^3}}+3y}\)</span></p>
</li><li><p><span class="math-tex">\( {{\sqrt{2y-2y^2}}+2y}\)</span></p>
</li></ol> <h2 id="content-id-1567048923-5"><b> Trigonometry Questions Solution</b></h2><p>The correct answer is <strong>option 4</strong> i.e.<span class="math-tex">\( {{\sqrt{2y-2y^2}}+2y}\)</span></p>

<p>Given,</p>

<p>⇒ tanθ = <span class="math-tex">\({{\sqrt{2y-2y^2}}\over2y}\)</span> = <span class="math-tex">\(P\over B\)</span></p>

<p>⇒ H<sup>2</sup> = B<sup>2</sup> + P<sup>2</sup></p>

<p>⇒ H<sup>2</sup> = 4y<sup>2</sup> + 2y - 2y<sup>2 </sup>= 2y<sup>2</sup> + 2y</p>

<p>⇒ H = <span class="math-tex">\(\sqrt{2y(y+1)}\)</span></p>

<p>⇒ sinθ = <span class="math-tex">\(P\over H\)</span> = <span class="math-tex">\({{\sqrt{2y-2y^2}}\over\sqrt{2y(y+1)}}\)</span></p>

<p>⇒ cosθ = <span class="math-tex">\(B\over H\)</span> = <span class="math-tex">\({2y}\over\sqrt{2y(y+1)}\)</span></p>

<p>Hence, the value of <span class="math-tex">\({{\sqrt{2y(y+1)}}} \times (\sin\theta+\cos\theta)\)</span></p>

<p>⇒ <span class="math-tex">\({{\sqrt{2y(y+1)}}} \times ({{\sqrt{2y-2y^2}}\over\sqrt{2y(y+1)}} + {{2y}\over\sqrt{2y(y+1)}})\)</span></p>

<p>⇒ <span class="math-tex">\({{\sqrt{2y(y+1)}}} \times ({{{\sqrt{2y-2y^2}}+2y}\over\sqrt{2y(y+1)}})\)</span></p>

<p>⇒ <span class="math-tex">\( {{\sqrt{2y-2y^2}}+2y}\)</span></p>
<h2 id="content-id-3210596487-6"><b> Trigonometry Questions Tips and Tricks</b></h2><img loading="lazy" src="https://study.kdcampus.live/questions-blog-pdf/Trigonometry_Questions_Tips_and_Tricks.png" alt="Trigonometry Questions Tips and Tricks" height="260" width="480"><ol><li>Try to solve Trigonometry Questions without taking any help from the solutions.</li><li>Trigonometry Questions require proper usage of concept so firstly read the question thoroughly and then use the right concept. </li><li>In case you're not able to solve the question in less than 30 seconds in the exam then you should skip the question and move to the next question.</li></ol><h3><b>Daily Current Affairs </b></h3><img loading="lazy" src="https://study.kdcampus.live/questions-blog-pdf/Daily_Current_Affairs.png" alt="Daily Current Affairs" height="260" width="480"><p>KD Live is providing Current Affairs on a daily basis for SSC and a current affairs quiz too for the practice. 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The correct answer is option 4 i.e.( {{s - Trigonometry Questions are asked in Ssc Chsl exams and your question has been explained by experts like Neetu Mam.

If tan sqrt 2y-2y - Trigonometry Questions for Ssc Chsl

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