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<html><body><h2 id="content-id-4165203879-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Selection Post 12th English Exam and the type of question asked in Selection Post 12th English exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-0842157936-3"><b>Question On Trigonometry </b></h2>If sin(90° − x) = cos(2x − 30°), and x is acute, find the value of x.
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Easy </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 32 Seconds </h3></div></div><h2 id="content-id-0192834567-4"><b> Trigonometry Questions Options</b></h2><ol><li><p>30°</p>
</li><li><p>45°</p>
</li><li><p>60°</p>
</li><li><p>15°</p>
</li></ol> <h2 id="content-id-6218054739-5"><b> Trigonometry Questions Solution</b></h2><p>The correct answer is<strong> option 1 </strong>i.e.<strong> 30°.</strong></p>

<p>sin(90° − x) = cos x</p>

<p>So,</p>

<p>cos x = cos(2x − 30°)</p>

<p>⇒ x = 2x − 30°</p>

<p>⇒ 30° = x</p>
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The correct answer is option 1 i.e. 30 - Trigonometry Questions are asked in Selection Post 12th English exams and your question has been explained by experts like Neetu Mam.

If sin 90 x cos - Trigonometry Questions for Selection Post 12th English

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