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<html><body><h2 id="content-id-3091486752-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Ssc Cgl Exam and the type of question asked in Ssc Cgl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-2689537014-3"><b>Question On Trigonometry </b></h2>If [cos2 θ/(cot2θ - cos2θ)] = 3, 0º < θ < 90º. Find the value of θ.
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 32 Seconds </h3></div></div><h2 id="content-id-6310879245-4"><b> Trigonometry Questions Options</b></h2><ol><li><p>30º</p>
</li><li><p>45º</p>
</li><li><p>60º</p>
</li><li><p>90º</p>
</li></ol> <h2 id="content-id-0852619347-5"><b> Trigonometry Questions Solution</b></h2><p> The correct answer is <strong>option 3</strong> i.e. <strong>60º.</strong></p>

<p><span style="font-size:12.0pt">⇒ </span>[cos<sup>2</sup>θ/(cot<sup>2</sup>θ - cos<sup>2</sup>θ)] = 3</p>

<p><span style="font-size:12.0pt">⇒ </span>[cos<sup>2</sup>θ/{(cos<sup>2</sup>θ/ sin<sup>2</sup>θ) - cos<sup>2</sup> θ}] = 3</p>

<p><span style="font-size:12.0pt">⇒ </span>[cos<sup>2</sup>θ/{(cos<sup>2</sup>θ - sin<sup>2</sup>θcos<sup>2</sup> θ)/sin<sup>2</sup> θ}] = 3</p>

<p><span style="font-size:12.0pt">⇒ </span>[cos<sup>2</sup>θ/{(cos<sup>2</sup>θ - sin<sup>2</sup>θcos<sup>2</sup> θ)/sin<sup>2</sup>θ}] = 3</p>

<p><span style="font-size:12.0pt">⇒ </span>[cos<sup>2</sup>θ × sin<sup>2</sup>θ/(cos<sup>2</sup>θ - sin<sup>2</sup>θcos<sup>2</sup>θ)] = 3</p>

<p><span style="font-size:12.0pt">⇒ </span>[cos<sup>2</sup>θ × sin<sup>2</sup> θ/{cos<sup>2</sup>θ (1 - sin<sup>2</sup>θ)}] = 3</p>

<p><span style="font-size:12.0pt">⇒ </span>[sin<sup>2</sup>θ/(1 - sin<sup>2</sup>θ)] = 3</p>

<p><span style="font-size:12.0pt">⇒ </span>[sin<sup>2</sup>θ/cos<sup>2</sup>θ] = 3</p>

<p><span style="font-size:12.0pt">⇒ </span>tan<sup>2</sup>θ = 3</p>

<p><span style="font-size:12.0pt">⇒ </span>tanθ = √3    (tan60º = √3)</p>

<p><span style="font-size:12.0pt">⇒ </span>tanθ = tan60º </p>

<p><span style="font-size:12.0pt">⇒ </span>θ = 60º </p>
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 The correct answer is option 3 i.e. 6 - Trigonometry Questions are asked in Ssc Cgl exams and your question has been explained by experts like Neetu Mam.

If cos2 cot2 - co - Trigonometry Questions for Ssc Cgl

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