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<html><body><h2 id="content-id-9682354017-2"><b>Algebra Questions Overview</b></h2><p>Algebra Questions have a good weightage in the Ssc Cgl Exam and the type of question asked in Ssc Cgl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Algebra Questions.</p><h2 id="content-id-3891620754-3"><b>Question On Algebra </b></h2>If 2(sqrt{2})x3 - 3(sqrt{3})y3 = ((sqrt{2x}-sqrt{3y})) (Ax2 - Bxy +Cy2), then the value of (sqrt{})(A2 + B2 + C2) is:
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 34 Seconds </h3></div></div><h2 id="content-id-3895760412-4"><b> Algebra Questions Options</b></h2><ol><li><p><span class="math-tex">\(\sqrt{19}\)</span></p>
</li><li><p><span class="math-tex">\(\sqrt{11}\)</span></p>
</li><li><p><span class="math-tex">\(\sqrt{17}\)</span></p>
</li><li><p><span class="math-tex">\(\sqrt{21}\)</span></p>
</li></ol> <h2 id="content-id-4251678039-5"><b> Algebra Questions Solution</b></h2><p>The correct answer is <strong>option 1</strong> i.e. <span class="math-tex">\(\sqrt{19}\)</span>.</p>

<p>x<sup>3</sup> - y<sup>3</sup> = (x - y)(x<sup>2 </sup>+ xy + y<sup>2</sup>)</p>

<p> 2<span class="math-tex">\(\sqrt{2}\)</span>x<sup>3</sup> - 3<span class="math-tex">\(\sqrt{3}\)</span>y<sup>3</sup> = (<span class="math-tex">\(\sqrt{2x}-\sqrt{3y}\)</span>) (Ax<sup>2</sup> - Bxy +Cy<sup>2</sup>)</p>

<p>⇒ (2√2x<sup>3</sup> - 3√3y<sup>3</sup>)/(√(2x) - √(3y)) = Ax<sup>2</sup> - Bxy + Cy<sup>2</sup></p>

<p>⇒ <span class="math-tex">\(\frac{(\sqrt2xÂ - \sqrt3y)(2x^2Â + 3y^2Â - (\sqrt6xy)}{\sqrt2x - \sqrt3y}\)</span> = Ax<sup>2</sup> - Bxy + Cy<sup>2</sup></p>

<p>= (2x<sup>2 </sup>- √6xy + 3y<sup>2</sup>) = = Ax<sup>2</sup> - Bxy + Cy<sup>2</sup></p>

<p>On comparing with Ax<sup>2</sup> - Bxy + Cy<sup>2</sup> -</p>

<p>A = 2</p>

<p>B = √6</p>

<p>C = 3</p>

<p>⇒ √(A<sup>2</sup> + B<sup>2</sup> + C<sup>2</sup>) = √{2<sup>2</sup> + (√6)<sup>2</sup> + 3<sup>2</sup>} = √(4 + 6 + 9) = √19</p>
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