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<html><body><h2 id="content-id-4526319708-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Ssc Chsl Exam and the type of question asked in Ssc Chsl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-0287496153-3"><b>Question On Trigonometry </b></h2>If (({1^4+tan^4	heta}) 	imes {cos^4	heta}	imes{1over cosec	heta}) = ({cosec	heta + ncos^3	heta}over cosec^2	heta)
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 31 Seconds </h3></div></div><h2 id="content-id-7689325410-4"><b> Trigonometry Questions Options</b></h2><ol><li><p>0</p>
</li><li><p>1</p>
</li><li><p>-1</p>
</li><li><p>-2</p>
</li></ol> <h2 id="content-id-5189423706-5"><b> Trigonometry Questions Solution</b></h2><p>The correct answer is <strong>option 4</strong> i.e.<strong>- 2.</strong></p>

<p>Solving L.H.S</p>

<p>⇒ <span class="math-tex">\(({1^4+tan^4\theta}) \times {cos^4\theta}\times{1\over cosec\theta}\)</span></p>

<p> ⇒ <span class="math-tex">\(({(1^2)^2+(tan^2\theta)^2}) \times {cos^4\theta}\times{1\over cosec\theta}\)</span></p>

<p> ⇒ <span class="math-tex">\(({(1^2)^2+(tan^2\theta)^2} +2tan\theta -2tan\theta) \times {cos^4\theta}\times{1\over cosec\theta}\)</span></p>

<p> ⇒ <span class="math-tex">\(({(1+tan^2\theta)^2} -2tan\theta) \times {cos^4\theta}\times{1\over cosec\theta}\)</span></p>

<p> ⇒ <span class="math-tex">\(({sec^2\theta)^2} -2tan\theta) \times {cos^4\theta}\times{1\over cosec\theta}\)</span></p>

<p> ⇒ <span class="math-tex">\(({{1\over cos^4\theta} -{2sin\theta\over cos\theta})} \times {cos^4\theta}\times{1\over cosec\theta}\)</span></p>

<p> ⇒ <span class="math-tex">\(({{1 -{2sin\theta cos^3\theta}} \over {cos^4\theta}})\times cos^4\theta \times{1\over cosec\theta}\)</span></p>

<p> ⇒ <span class="math-tex">\(({{1 -{2sin\theta cos^3\theta)}}} \times{1\over cosec\theta}\)</span></p>

<p> ⇒ <span class="math-tex">\(({{1 -{2sin\theta cos^3\theta)}}}\over{cosec\theta}\)</span></p>

<p> ⇒ <span class="math-tex">\({1\over coesc\theta} -{2cos^3\theta\over cosec^2\theta}\)</span></p>

<p> ⇒ <span class="math-tex">\({{coesc\theta} -{2cos^3\theta}\over cosec^2\theta}\)</span></p>

<p>Comparing with R.H.S</p>

<p> ⇒ <span class="math-tex">\({{coesc\theta} -{2cos^3\theta}\over cosec^2\theta}\)</span> = <span class="math-tex">\({cosec\theta + ncos^3\theta}\over cosec^2\theta\)</span></p>

<p> ⇒ n = -2</p>
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The correct answer is option 4 i.e.- 2. - Trigonometry Questions are asked in Ssc Chsl exams and your question has been explained by experts like Neetu Mam.

If 1 4 tan 4 heta - Trigonometry Questions for Ssc Chsl

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