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<html><body><h2 id="content-id-9716823045-2"><b>Quadratic Equation Questions Overview</b></h2><p>Quadratic Equation Questions have a good weightage in the Ssc Chsl Exam and the type of question asked in Ssc Chsl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Quadratic Equation Questions.</p><h2 id="content-id-9572634180-3"><b>Question On Quadratic Equation </b></h2>Equation I: x2 - mx + 36 = 0 (Roots are equal)

Equation II: ny2 - 13y + 12 = 0 (Product of roots = 2)

What is the difference between the larger root of Equation I and the larger root of Equation II?
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Easy </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 37 Seconds </h3></div></div><h2 id="content-id-0381925746-4"><b> Quadratic Equation Questions Options</b></h2><ol><li><p>4</p>
</li><li><p>2</p>
</li><li><p>4.5</p>
</li><li><p>6</p>
</li><li><p>3.5</p>
</li></ol> <h2 id="content-id-9236480571-5"><b> Quadratic Equation Questions Solution</b></h2><p>The correct answer is <strong>option 3</strong> i.e. <strong>4.5.</strong></p>

<p>Equation I: x<sup>2</sup> - mx + 36 = 0</p>

<p>Roots are equal</p>

<p>b<sup>2</sup> − 4ac = 0</p>

<p>m<sup>2</sup> − 4 × 1 × 36 = 0</p>

<p>m<sup>2</sup> − 144 = 0</p>

<p>m = 12</p>

<p>x<sup>2</sup> − 12x + 36 = 0</p>

<p>(x − 6)<sup>2 </sup>= 0</p>

<p>X = 6</p>

<p>Equation II: ny<sup>2</sup> - 13y + 12 = 0</p>

<p>Product of roots = 2</p>

<p>Product of roots = c/a</p>

<p>12/n = 2</p>

<p>n = 6</p>

<p>Equation: 6y<sup>2</sup> − 13y + 6 = 0</p>

<p>6y<sup>2</sup> − 9y − 4y + 6 = 0</p>

<p>3y(2y − 3) − 2(2y − 3) = 0</p>

<p>(2y − 3)(3y − 2) = 0</p>

<p>y = 2/3, 3/2</p>

<p>Larger root of Equation I = 6</p>

<p>Larger root of Equation II = 1.5</p>

<p>Required difference</p>

<p>6 − 1.5 = 4.5</p>
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The correct answer is option 3 i.e. 4.5. - Quadratic Equation Questions are asked in Ssc Chsl exams and your question has been explained by experts like Neetu Mam.

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