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<html><body><h2 id="content-id-0146798253-2"><b>Caselets Questions Overview</b></h2><p>Caselets Questions have a good weightage in the Ssc Chsl Exam and the type of question asked in Ssc Chsl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Caselets Questions.</p><h2 id="content-id-7460192385-3"><b> Comprehension On Caselets Questions</b></h2>A can complete a work alone in x days, while B takes 10 days more than A; together they complete 50% of the work in 6 days. C is 50% more efficient than B, while C and D together can complete 80% of the work in 12 days. A and B start working together for 3 days; thereafter A and C work for 5 days, with A working at 75% and C at 125% of their normal efficiencies. After that, B and D work together at their normal efficiencies till the remaining work is completed.
<h2 id="content-id-3964821057-4"><b>Question On Caselets </b></h2>B works at 150% of his normal efficiency and D at 200%. In how many days will they complete the same amount of work that A and C completed together in the given 5 days?
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Easy </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 59 Seconds </h3></div></div><h2 id="content-id-9253706148-5"><b> Caselets Questions Options</b></h2><ol><li><p>8 days</p>
</li><li><p>6 days</p>
</li><li><p>4 days</p>
</li><li><p>5 days</p>
</li><li><p>7 days</p>
</li></ol> <h2 id="content-id-3154082796-6"><b> Caselets Questions Solution</b></h2><p>The correct answer is <strong>option 2</strong> i.e. <strong>6 days</strong></p>

<p>A + B efficiency = 50%/6 = 1/12</p>

<p>1/x + 1/(x + 10) = 1/12</p>

<p>12(2x + 10) = x(x + 10)</p>

<p>x = 20</p>

<p>So, A = 20 days, B = 30 days.</p>

<p>Total work = LCM of 20 and 30 = 60 units</p>

<p>A efficiency = 60/20 = 3 units/day</p>

<p>B efficiency = 60/30 = 2 units/day</p>

<p>C efficiency = 2 × 150% = 3 units/day</p>

<p>C + D efficiency = 80% of 60/12 = 4 units/day</p>

<p>D efficiency = 4 − 3 = 1 unit/day</p>

<p>First 3 days: (3 + 2) × 3 = 15 units</p>

<p>Next 5 days: (3 × 75% + 3 × 125%) × 5 = 30 units</p>

<p>Remaining work = 60 − 15 − 30 = 15 units</p>

<p>B + D efficiency = 2 + 1 = 3 units/day</p>

<p>Time = 15/3 = 5 days</p>

<p>Total time = 3 + 5 + 5 = 13 days</p>

<p>A efficiency = 3 units/day, C efficiency = 3 units/day</p>

<p>A + C efficiency = 3 + 3 = 6 units/day</p>

<p>Work in 5 days = 6 × 5 = 30 units</p>

<p>B at 150% = 2 × 150% = 3 units/day</p>

<p>D at 200% = 1 × 200% = 2 units/day</p>

<p>B + D efficiency = 3 + 2 = 5 units/day</p>

<p>Time = 30/5 = 6 days</p>
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The correct answer is option 2 i.e. 6 da - Caselets Questions are asked in Ssc Chsl exams and your question has been explained by experts like Neetu Mam.

B works at 150 of his no - Caselets Questions for Ssc Chsl

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