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<html><body><h2 id="content-id-0263897451-2"><b>Geometry Questions Overview</b></h2><p>Geometry Questions have a good weightage in the Ssc Chsl Exam and the type of question asked in Ssc Chsl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Geometry Questions.</p><h2 id="content-id-5296308417-3"><b>Question On Geometry </b></h2>ABC is a triangle lying inside the circle in which ∠BAC = 120° side AB = 14.25 cm and side AC = 16.2 cm then find the area of the shaded area.


<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 33 Seconds </h3></div></div><h2 id="content-id-9024518736-4"><b> Geometry Questions Options</b></h2><ol><li><p>196 cm<sup>2</sup></p>
</li><li><p>241 cm<sup>2</sup></p>
</li><li><p>148 cm<sup>2</sup></p>
</li><li><p>117 cm<sup>2</sup></p>
</li></ol> <h2 id="content-id-3164259708-5"><b> Geometry Questions Solution</b></h2><p>The correct answer is<strong> option 3</strong> i.e. <strong>148 cm<sup>2</sup></strong>.</p>

<p><img loading="lazy" alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/Urgent%20DiagrmX5_05.04.2024_D21.png" style="height:176px; width:181px"></p>

<p>∠BAC = 120°</p>

<p>AB = 14.25 cm</p>

<p>AC = 16.2 cm </p>

<p>Area of the shaded region = Area of circle - area of triangle</p>

<p>Area of triangle = <span class="math-tex">\(\frac{1}{2}\)</span>(AB × AC) × Sin A</p>

<p>=  <span class="math-tex">\(\frac{1}{2}\)</span>(14.25 × 16.2) × Sin 120°            [sin (90 + θ) = Cosθ]</p>

<p>=  <span class="math-tex">\(\frac{1}{2}\)</span>(230.85) × Cos30°   </p>

<p>=  <span class="math-tex">\(\frac{1}{2}\)</span>(230.85) × <span class="math-tex">\(\frac{\sqrt3}{2}\)</span></p>

<p>= 99.59 cm<sup>2</sup></p>

<p>Now using the cosine rule</p>

<p>Cos θ = <span class="math-tex">\(\frac{AB^2+AC^2-BC^2}{2AB.AC}\)</span></p>

<p>Cos 120 = <span class="math-tex">\(\frac{14.25^2+16.2^2-BC^2}{2\times14.25\times16.2}\)</span></p>

<p>1/2 = <span class="math-tex">\(\frac{465.50-BC^2}{461.7}\)</span></p>

<p>461.7 = 931 - 2BC<sup>2</sup></p>

<p>BC = <span class="math-tex">\(\sqrt{234.65}\)</span></p>

<p>BC = 15.32 Cm</p>

<p>Circum radius of circle R = abc/(4 area of triangle)</p>

<p>R = (14.25 × 16.2 × 15.32)/(4 × 99.59)</p>

<p>R = 8.88 Cm</p>

<p>Area of circle = πR<sup>2</sup></p>

<p>= 3.14 × 8.88<sup>2</sup></p>

<p>= 247.60 cm<sup>2</sup></p>

<p>Area of the shaded region = Area of circle - area of triangle = 247.60 - 99.59 = 148.01 = 148 cm<sup>2</sup></p>
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Which of the following is - GK Misc Questions for Ssc Chsl

What is the range of the - GK Misc Questions for Ssc Chsl

The correct answer is option 3 i.e. 148 - Geometry Questions are asked in Ssc Chsl exams and your question has been explained by experts like Neetu Mam.

ABC is a triangle lying i - Geometry Questions for Ssc Chsl

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