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<html><body><h2 id="content-id-6418570239-2"><b>Geometry Questions Overview</b></h2><p>Geometry Questions have a good weightage in the Ssc Stenographer Exam and the type of question asked in Ssc Stenographer exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Geometry Questions.</p><h2 id="content-id-4973615802-3"><b>Question On Geometry </b></h2>A solid sphere whose radius is 21 cm is melted and recast into a regular pyramid of square base. If height of the pyramid is 66 cm, then what is the length of each side of the base of the pyramid? (Use (pi) = (rac{22}{7}))

(MTS 2021)
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Easy </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 37 Seconds </h3></div></div><h2 id="content-id-9158067243-4"><b> Geometry Questions Options</b></h2><ol><li><p>68 cm</p>
</li><li><p>85 cm</p>
</li><li><p>42 cm</p>
</li><li><p>48 cm</p>
</li></ol> <h2 id="content-id-5864793120-5"><b> Geometry Questions Solution</b></h2><p>The correct answer is <strong>option 3</strong> i.e. <strong>42 cm</strong>.</p>

<p>Volume of sphere = Volume of pyramid<br>
<span class="math-tex">\(\frac{4}{3}\)</span><span class="math-tex">\(\pi\)</span>R<sup>3</sup> = <span class="math-tex">\(\frac{1}{3}\)</span> <span class="math-tex">\(\times\)</span> Base Area <span class="math-tex">\(\times\)</span> H <br>
4<span class="math-tex">\(\pi\)</span>R<sup>3</sup> = (x)<sup>2</sup> <span class="math-tex">\(\times\)</span> H <br>
4 <span class="math-tex">\(\times\)</span> <span class="math-tex">\(\frac{22}{7}\)</span> <span class="math-tex">\(\times\)</span> 21 <span class="math-tex">\(\times\)</span> 21 <span class="math-tex">\(\times\)</span> 21 =(x)<sup>2</sup> <span class="math-tex">\(\times\)</span> 66 <br>
4 <span class="math-tex">\(\times\)</span> 21 <span class="math-tex">\(\times\)</span> 21 = x2 <br>
x = <span class="math-tex">\(\sqrt{4\times\ 21\ \times\ 21}\)</span> = 2 <span class="math-tex">\(\times\)</span> 21 = 42 cm</p>
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The correct answer is option 3 i.e. 42  - Geometry Questions are asked in Ssc Stenographer exams and your question has been explained by experts like Neetu Mam.

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