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<html><body><h2 id="content-id-5346872019-2"><b>Mensuration 3D Questions Overview</b></h2><p>Mensuration 3D Questions have a good weightage in the Ssc Chsl Exam and the type of question asked in Ssc Chsl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Mensuration 3D Questions.</p><h2 id="content-id-5893142706-3"><b>Question On Mensuration 3D </b></h2>A solid metallic right circular cylinder has a radius of r cm and a height of h cm. The sum of its radius and height is 35 cm, and its Total Surface Area (TSA) is 3080 cm². This cylinder is completely melted and recast into two different solid shapes: a single solid sphere of radius R cm and a single solid right circular cone having the same base radius as the cylinder and a height of 9 cm. (take π = 22/7)


	
		
			Column I 
			Column II 
		
	
	
		
			(A) The numerical value of (Volume of Cylinder ÷ 7)
			(P) A specific number whose sum of the digits is 21, and it represents the total volume of the recast cone.
		
		
			(B) The value of the expression: (Volume of Sphere − 8,344)
			(Q) The total cost of painting the Curved Surface Area (CSA) of the original cylinder at the rate of â&#130;¹2 per cm2.
		
		
			(C) The value of the expression: (r × h × 10) − 196
			(R) The capacity (in cm3) of a cubical box whose edge length is equal to the radius (r) of the cylinder.
		
	



<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Easy </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 73 Seconds </h3></div></div><h2 id="content-id-2681395704-4"><b> Mensuration 3D Questions Options</b></h2><ol><li><p>(A) → (Q), (B) → (P), and (C) → (R)</p>
</li><li><p>Only (A) → (P), (C) → (R)</p>
</li><li><p>(A) → (P), (B) → (R), and (C) → (R)</p>
</li><li><p>Only (A) → (P), (B) → (R),</p>
</li><li><p>A) → (P), (B) → (Q), and (C) → (R)</p>
</li></ol> <h2 id="content-id-7493056128-5"><b> Mensuration 3D Questions Solution</b></h2><p>The correct answer is <strong>option 3 </strong>i.e. <strong>(A) → (P), (B) → (R), and (C) → (R).</strong></p>

<p><strong>Given:</strong></p>

<p>Radius of cylinder = r cm</p>

<p>Height of cylinder = h cm</p>

<p>r + h = 35</p>

<p>Total Surface Area (TSA) of cylinder = 3080 cm<sup>2</sup></p>

<p>π = 22/7</p>

<p>TSA of cylinder = 2πr(r + h)</p>

<p>2 × (22/7) × r × 35 = 3080</p>

<p>220r = 3080</p>

<p>r = 14 cm</p>

<p>h = 35 − 14 = 21 cm</p>

<p><strong>Volume of Cylinder:</strong></p>

<p>V = πr<sup>2</sup>h = (22/7) × 14<sup>2</sup> × 21</p>

<p>= (22/7) × 196 × 21</p>

<p>= 12936 cm<sup>3</sup></p>

<p><strong>Since the cylinder is melted and recast into a sphere and a cone together,</strong></p>

<p>Volume of Cylinder = Volume of Sphere + Volume of Cone</p>

<p><strong>Volume of Cone:</strong></p>

<p>V = (1/3)πr<sup>2</sup>h = (1/3) × (22/7) × 14<sup>2</sup> × 9</p>

<p>= (1/3) × (22/7) × 196 × 9</p>

<p>= 1848 cm<sup>3</sup></p>

<p>Volume of Sphere = Volume of Cylinder − Volume of Cone</p>

<p>= 12936 − 1848 = 11088 cm<sup>3</sup></p>

<p><strong>Column I (A):</strong></p>

<p>Volume of Cylinder ÷ 7 = 12936 ÷ 7 = 1848</p>

<p><strong>Column II (P):</strong></p>

<p>Volume of recast cone = 1848 cm<sup>3</sup></p>

<p>Sum of digits of 1848</p>

<p>= 1 + 8 + 4 + 8</p>

<p>= 21</p>

<p>Therefore,</p>

<p><strong>(A) → (P)</strong></p>

<p><strong>Column I (B):</strong></p>

<p>Volume of Sphere − 8344</p>

<p>= 11088 − 8344</p>

<p>= 2744</p>

<p><strong>Column II (R):</strong></p>

<p>Capacity of cubical box = r<sup>3</sup> = 14<sup>3</sup> = 2744 cm<sup>3</sup></p>

<p>Therefore,</p>

<p><strong>(B) → (R)</strong></p>

<p><strong>Column I (C):</strong></p>

<p>(r × h × 10) − 196</p>

<p>= (14 × 21 × 10) − 196</p>

<p>= 2940 − 196</p>

<p>= 2744</p>

<p>Therefore,</p>

<p><strong>(C) → (R)</strong></p>

<p><strong>Column II (Q):</strong></p>

<p>Curved Surface Area (CSA) of cylinder</p>

<p>= 2πrh = 2 × (22/7) × 14 × 21 = 1848 cm<sup>2</sup></p>

<p>Cost of painting at â&#130;¹2 per cm<sup>2</sup> = 1848 × 2 = â&#130;¹3696</p>

<p><strong>Final Matching:</strong></p>

<p>(A) → (P)</p>

<p>(B) → (R)</p>

<p>(C) → (R)</p>
<h2 id="content-id-2413567980-6"><b> Mensuration 3D Questions Tips and Tricks</b></h2><img loading="lazy" src="https://study.kdcampus.live/questions-blog-pdf/Mensuration_3D_Questions_Tips_and_Tricks.png" alt="Mensuration 3D Questions Tips and Tricks" height="260" width="480"><ol><li>Try to solve Mensuration 3D Questions without taking any help from the solutions.</li><li>Mensuration 3D Questions require proper usage of concept so firstly read the question thoroughly and then use the right concept. </li><li>In case you're not able to solve the question in less than 30 seconds in the exam then you should skip the question and move to the next question.</li></ol><h3><b>Daily Current Affairs </b></h3><img loading="lazy" src="https://study.kdcampus.live/questions-blog-pdf/Daily_Current_Affairs.png" alt="Daily Current Affairs" height="260" width="480"><p>KD Live is providing Current Affairs on a daily basis for SSC and a current affairs quiz too for the practice. 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The correct answer is option 3 i.e. (A - Mensuration 3D Questions are asked in Ssc Chsl exams and your question has been explained by experts like Neetu Mam.

 Mensuration 3D Questions Tips and Tricks

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