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<html><body><h2 id="content-id-4153728069-2"><b>Time And Work Questions Overview</b></h2><p>Time And Work Questions have a good weightage in the Ssc Chsl Exam and the type of question asked in Ssc Chsl exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Time And Work Questions.</p><h2 id="content-id-7650234918-3"><b>Question On Time And Work </b></h2>A, B, and C can finish a work in 24, 30, and 40 days respectively. They begin together, but C leaves x days before the completion of the work and B leaves (x + 2) days before the completion. If the total work is finished in 14 days, find the value of x.
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Easy </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 40 Seconds </h3></div></div><h2 id="content-id-3859406712-4"><b> Time And Work Questions Options</b></h2><ol><li><p>5<span class="math-tex">\(\frac47\)</span> days</p>
</li><li><p>5<span class="math-tex">\(\frac5 7\)</span> days</p>
</li><li><p>6<span class="math-tex">\(\frac5 7\)</span> days</p>
</li><li><p>7<span class="math-tex">\(\frac2 7\)</span> days</p>
</li><li><p>5<span class="math-tex">\(\frac5 9\)</span> days</p>
</li></ol> <h2 id="content-id-8751342960-5"><b> Time And Work Questions Solution</b></h2><p>The correct answer is <strong>option 2</strong> i.e. <strong>5</strong><span class="math-tex">\(\frac5 7\)</span> <strong>days</strong>.</p>

<p>Efficiency of A = 1 / 24</p>

<p>Efficiency of B = 1 / 30</p>

<p>Efficiency of C = 1 / 40</p>

<p>A works for 14 days</p>

<p>Work done by A = 14 / 24 = 7 / 12</p>

<p>C leaves x days before completion</p>

<p>Days worked by C = 14 − x</p>

<p>Work done by C = (14 − x) / 40</p>

<p>B leaves (x + 2) days before completion</p>

<p>Days worked by B = 14 − (x + 2) = 12 − x</p>

<p>Work done by B = (12 − x) / 30</p>

<p>Total work = 1</p>

<p>7 / 12 + (14 − x) / 40 + (12 − x) / 30 = 1</p>

<p>⇒ 70 + 3(14 − x) + 4(12 − x) = 120</p>

<p>⇒ 70 + 42 − 3x + 48 − 4x = 120</p>

<p>⇒ 160 − 7x = 120</p>

<p>⇒ 7x = 40</p>

<p>x = 40 / 7 = 5<span class="math-tex">\(\frac5 7\)</span> days</p>
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The correct answer is option 2 i.e. 5( - Time And Work Questions are asked in Ssc Chsl exams and your question has been explained by experts like Neetu Mam.

A B and C can finish a - Time And Work Questions for Ssc Chsl

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