Mridul Mehta has very keen interest in the government exams and know a lot about the exam patterns, question difficulties etc.

10+ Years Experience in the Government Exams

<h3>Here, we are going to learn all about the BODMAS rule, what it is, where to use it along with some mind-blowing formulae which will transfer you in a human calculator.</h3>

<h3>E.g. 221 ÷ 13 × √576 + (10)2 = ?</h3>

<h3>We are completely clueless about where to start right now, so let’s start from left:</h3>

<h3>⇒ 221 ÷ 13 × 24 + 100 = ?</h3>

<h3>⇒ 221 ÷ 13 × 124 = ?</h3>

<h3>⇒ 221 ÷ 1612 = ? ⇒ 7.290 (Approx.)</h3>

<h3>Which is wrong, so how to approach these types of questions?</h3>

<h3>Is there a specific method to approach them?</h3>

<h3>Yes, VBODMAS rule.</h3>

<h2>VBODMAS RULE:</h2>

<h3>Full form of VBODMAS is:</h3>

<table border="1" cellpadding="1" cellspacing="1" style="width:320px">
	<tbody>
		<tr>
			<td style="background-color:#000033">Sr. No.</td>
			<td style="background-color:#000033">Alphabet</td>
			<td style="background-color:#000033">Significance</td>
		</tr>
		<tr>
			<td>1.</td>
			<td>V</td>
			<td>Vinculum or Bar</td>
		</tr>
		<tr>
			<td>2.</td>
			<td>B</td>
			<td>Brackets</td>
		</tr>
		<tr>
			<td>3.</td>
			<td>O</td>
			<td>Of</td>
		</tr>
		<tr>
			<td>4.</td>
			<td>D</td>
			<td>Division</td>
		</tr>
		<tr>
			<td>5.</td>
			<td>M</td>
			<td>Multiplication</td>
		</tr>
		<tr>
			<td>6.</td>
			<td>A</td>
			<td>Addition</td>
		</tr>
		<tr>
			<td>7.</td>
			<td>S</td>
			<td>Subtraction</td>
		</tr>
	</tbody>
</table>

<h3>For every question we have to do each step from up to bottom</h3>

<h3>Let’s take an example and try to solve it.</h3>

<h3>E.g.  221 ÷ 13 × √576 + (10)2 = ?</h3>

<h3>Step- 1: First try to Solve √576 and (10)2</h3>

<h3>⇒ 221 ÷ 13 × 24 + 100 = ?</h3>

<h3>Step- 2: Division</h3>

<h3>⇒ 221 ÷ 13 × 24 + 100 = ?</h3>

<h3>⇒ 17 × 24 + 100 = ?</h3>

<h3>Step- 3: Multiplication</h3>

<h3>⇒ 17 × 24 + 100 = ? ⇒ 408 + 100 = ?</h3>

<h3>Step- 4: Addition</h3>

<h3>⇒ 408 + 100 = ? ⇒ 508 (Ans).</h3>

<h3>Tip- While solving brackets first open small () then curly {} and last big brackets []</h3>

<h3>E.g.  [(2211 ÷ 67)2 – 21 × √(256 )] ÷ (549 – 213) = ? ÷ 1344</h3>

<h3>Let’s apply VBODMAS rule here</h3>

<h3>Step-1: Let’s Solve √256</h3>

<h3>⇒ [(2211 ÷ 67)2 - 21 × 16] ÷ (549 - 213) = ? ÷ 1344 </h3>

<h3>Step-2: Start opening the Brackets</h3>

<h3>⇒ [(2211 ÷ 67)2 - 21 × 16] ÷ (549 – 213) = ? ÷ 1344</h3>

<h3>⇒ [(33)2 – 21 × 16] ÷ 336 = ? ÷ 1344</h3>

<h3>Step-3: Now we have to first simplify equation in bracket then open it by VBODMAS</h3>

<h3>⇒ [1089 – 21 × 16] ÷ 336 = ? ÷ 1344</h3>

<h3>⇒ [1089 – 336] ÷ 336 = ? ÷ 1344</h3>

<h3>Step-4: Now open the bracket</h3>

<h3>⇒ [1089 –336] ÷ 336 = ? ÷ 1344</h3>

<h3>⇒ 753 ÷ 336 = ? ÷ 1344</h3>

<h3>Step-5: Division</h3>

<h3>⇒ 753 ÷ 336 = ? ÷ 1344</h3>

<h3>⇒ 753 × 1344 ÷ 336 = ? ⇒ 753 × 4</h3>

<h3>⇒ 3012 (Ans).</h3>

<h3>E.g.  1/6 of 355 of 1/5 of 2160 + √3969 - 448.98 = ? </h3>

<h3>Step-1: first solve of</h3>

<h3>1/5 of 2160 ⇒ 1/5 × 2160 ⇒ 432</h3>

<h3>And 1/6 of 355 ⇒ 355/6</h3>

<h3>So, we got,</h3>

<h3>⇒ 355/6 of 432 + 37 – 448.98</h3>

<h3>⇒ 355/6 × 432 + 37 – 448.98</h3>

<h3>Step-3: Division</h3>

<h3>⇒ 355 × 72 + 37 – 448.98</h3>

<h3>Step-4: Multiplication</h3>

<h3>⇒ 355 × 72 + 37 – 448.98 ⇒ 25560 + 37 – 448.98</h3>

<h3>Step-5: Addition</h3>

<h3>⇒ 25560 + 37 – 448.98</h3>

<h3>⇒ 25597 – 448.98</h3>

<h3>Step-6: Subtraction</h3>

<h3>⇒ 25597 – 448.98 = 25,148.02 (Ans).</h3>

<h3>E.g.  28/9 × 144/12 ÷ 17/5 + 13/17 </h3>

<h3>Step-1: By BODMAS rule we would firstly (D) Divide</h3>

<h3>⇒ 28/9 × 12÷ 17/5 + 13/17</h3>

<h3>⇒ 28/9 × 60/17 + 13/17</h3>

<h3>Step-2: Multiplication</h3>

<h3>⇒ 28/9 × 60/17 + 13/17 = 560/51 + 13/17</h3>

<h3>Step-3: Addition</h3>

<h3>⇒ (560 + 39)/51 = 599/51 (Ans).</h3>

<h3>As we saw by using this concept it would lead to the correct answer however the question is how tedious. Try to solve the questions regarding this topic. It will help you in all other topics of Quant. We will come back with another topic of Quant in our next blog.</h3>

Ace VBODMAS

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