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Average questions are a major type of questions asked in competitive exams. These questions carry a weightage of 1-2 questions (2-4 marks) in SSC exams and 1-2 questions in bank exams. To get a good rank in competitive exams, you should have a good hold on the concepts of Average.

Here are some tips for solving Average questions: Identify the key information in the question, Use the appropriate formula as there are many different formulas that can be used to calculate the average. Practice solving a variety of average questions, Use shortcuts and formulas. 

So, we have attached 10 questions of Average for you to practice with. You should aim to solve these questions in less than half a minute for each.

 

<h2>Practice Questions on Average</h2>

You can also download the Average questions and answers pdf. Just click on the Download PDF button. So let&#39;s start with the very first question.

Q:1 In a company, the average salary of male employees is ₹x, and that of female employees is ₹(x + 8000). The ratio of male to female employees in the company is 9 : 7. If the average salary of all the employees in the company is ₹27500, then find the average of total male employees and total female employees.

1. 40

2. 32

3. 44

4. Can’t be determined

(Difficulty: 4, Estimated Time: 25 Seconds) This was a tricky question!

Q:2 MP’s from 5 different parties A, B, C, D and E are present in the Parliament. The average number of MP’s from parties A and C is 100 and that from parties B and E is 90. The number of MP’s from party B is 50 more than that of party C. The total number of MP’s from parties A and E is 230. The number of MP’s of party D is 20 more than that of party B. Find the total number of MP’s from parties A, E and D.

1. 280

2. 600

3. 350

4. 440

(Difficulty: 4, Estimated Time: 25 Seconds) It is not an easy one but I think now you&#39;re prepared for it. Did you guess it right?

Q:3 The average number of people living in each house in a society having 47 houses is 4. If this average decreased by 0.2 when 2 families left the society then, what is the total number of people in 2 families which left?

1. 19

2. 14

3. 17

4. 15

(Difficulty: 3, Estimated Time: 20 Seconds) Another calculative one, but you will have to solve such questions within time!

Q:4 In a class, the number of boys is 10 more than that of girls. The average weight of a boy and a girl is 48 kg and 32 kg, respectively and the average weight of each student in the class is 41 kg. Find the total number of students (boys + girls) in the class.

1. 65

2. 80

3. 55

4. 34

(Difficulty: 2, Estimated Time: 15 Seconds) This was quite easy!

Q:5 The average number of boys in classes &#39;A&#39; and &#39;B&#39; together is 46 and class &#39;A&#39; has 8 less boys than class &#39;B&#39;. The average weight of a boy in class &#39;A&#39; is 45 kg and the total weight of all boys in class &#39;B&#39; is 410 kg more that the total weight of all boys in class &#39;A&#39;. Find the average weight of a boy in class &#39;B&#39;.

1. 40 kg

2. 52 kg

3. 33 kg

4. 46 kg

(Difficulty: 3, Estimated Time: 20 Seconds) We&#39;re halfway through. Have you got all your questions correct so far?

Q:6 The present average age of Tanish and Vikesh is 18 years. The present average age of Tanish, Vikesh, and Ashish is 20 years. The difference between the present ages of Tanish and Dinesh is 12 years. Find the present age of Tanish if the present average age of Tanish, Vikesh, Dinesh, and Ashish is 24 years.

1. 24 years

2. 20 years

3. 32 years

4. 40 years

(Difficulty: 4, Estimated Time: 30 Seconds) This was also a tricky one!

Q:7 The average age of a group of 60 students is 15 years. If 3 students whose ages are 17 years, 24 years and _____ years is replaced by 3 new students whose ages are ____ years, 22 years and 31 years, then the new average age of the group increases by 0.5 years.

The values given in which of the following options will fill the blanks in the same order in which is it given to make the above statement true:

A. 27, 45

B. 44, 64

C. 19, 37

1. Only A

2. Only B

3. Only A and C

4. All A, B and C

(Difficulty: 4, Estimated Time: 25 Seconds) This was a new type of question, but I think now you&#39;re prepared for it. 

Q:8 The average age of a family having five members is 42 years and the age of the oldest member of the family is 76 years. In the same year, a member whose age is 32 years has married a girl whose age is 30 years and after marriage, the average age of the family (including the bride) is reduced by 2 years. If the ratio of the age of the other three members (other than the oldest member, the member who got married and his bride) is 5 : 14 : 15, respectively then find the difference between the age of the oldest and the age of the youngest member.

1. 56 years

2. 61 years

3. 38 years

4. 65 years

(Difficulty: 4, Estimated Time: 25 Seconds) Tough questions alert!

Q:9 In a class, there are ‘x’ students and the average weight of the students is ‘y’ kg. If one new student whose weight is 50 kg is added, then the average weight of the class is increased by 1 kg. If one more student whose weight is 50 kg is added, then the average weight of the class increases by 1.5 kg over the original average. Which of the following can be found according to the given information?

(i) If Anant joins the class, the average weight of the class increases by 0.5 kg, find the weight of Anant.

(ii) The number of students in the class.

(iii) Find the value of (y – 3x)

1. Only (i)

2. Only (ii)

3. Only (iii)

4. All (i), (ii) and (iii)

(Difficulty: 3, Estimated Time: 20 Seconds) Practice and get fast with your calculations!

Q:10 A cricketer has played &#39;a&#39; matches and scored average of &#39;b&#39; runs. If the cricketer plays &#39;c&#39; more matches and scores average of &#39;d&#39; runs in those matches, what will be the cricketer&#39;s average runs per match?

1. \(\frac{b+a d}{d+a}\)

2. \(\frac{a b+a d}{a+c}\)

3. \(\frac{a +b d}{a+c}\)

4. None of these

(Difficulty: 2, Estimated Time: 15 Seconds) This was an easy one. Did you guess them all correctly?

<h2>Answer Key</h2>

Let&#39;s check out your score in this test.

<table border="0" cellpadding="1" cellspacing="1">
	<tbody>
		<tr>
			<td>1. (4)</td>
			<td>2. (3)</td>
			<td>3. (3)</td>
			<td>4. (2)</td>
			<td>5. (4)</td>
		</tr>
		<tr>
			<td>6. (1)</td>
			<td>7. (3)</td>
			<td>8. (2)</td>
			<td>9. (4)</td>
			<td>10. (2)</td>
		</tr>
	</tbody>
</table>

Comment below your score, considering each question has 1 mark only. If you scored 8 to 10, congratulations! You are one step closer to selection. If you have scored 5 to 8 marks, then you are doing well, keep it up. If you have scored less than 5 marks then you need to work a little harder on this subject. But don&#39;t worry, we are here to help you master the subject.

Let&#39;s check the answers and solutions and try to find out what went wrong. 
 

<h2>Answers and Solutions</h2>

Q:1 The correct answer is option 4 i.e. Can’t be determined.

Let the number of male employees and female employees in the company be ‘9y’ and ‘7y’ respectively.

So,

⇒ (9yx + 7y(x + 8000))/(9y + 7y) = 27500

⇒ 9x + 7x + 56000 = 440000

⇒ x = 24000

Since we can’t find the value of ‘y’.

So, we can’t determine the required average

 

Q:2 The correct answer is option 3 i.e. 350

Let there are a, b, c, d, and e number of MP’s are there from A, B, C, D and E respectively.

According to the question,

(a + c)/2 = 100

Or, a + c = 200.... (1)

(b + e)/2 = 90

Or, b + e = 180.... (2)

Adding equation (1) and (2)

a + c + b + e = 380..... (3)

b – c = 50..... (4)

Adding equation (3) and (4), we get

a + 2b + e = 430

Or, 2b = 430 – 230 (Since, a + e = 230)

Or, 2b = 200

Or, b = 100

c = 100 – 50 = 50

a = 200 – 50 = 150

e = 180 – 100 = 80

d = b + 20 = 120

Total number of MP’s from A, E and D = 150 + 80 + 120 = 350

 

Q:3 The correct answer is option 3 i.e. 17.

The average number of people living in each house in a society having 47 houses is 4

So, Total number of people living in 47 houses = 47 × 4 = 188

The average decreased by 0.2 when 2 families left the society

So, Total number of people in 45 houses now = 45 × (4 – 0.2) = 171

Hence, Total number of people in 2 families which left = 188 – 171 = 17

 

Q:4 The correct answer is option 2 i.e. 80

Let the number of girls in the class = ‘x’

Then, number of boys in the class = (x + 10)

Total weight of all boys in the class = (x + 10) × 48 = (48x + 480) kg

Total weight of all girls in the class = x × 32 = 32x kg

So, total weight of all the students in the class = (48x + 32x + 480) = (80x + 480) kg

Also, total weight of all the students in the class = (x + x + 10) × 41 = (82x + 410) kg

So, 80x + 480 = 82x + 410

Or, x = (70/2) = 35

So, total number of students in the class = x + x + 10 = 35 + 35 + 10 = 80

 

Q:5 The correct answer is option 4 i.e. 46 kg.

The sum of the number of boys in classes &#39;A&#39; and B&#39; = (46 × 2) = 92

Let the number of boys in class &#39;A&#39; = &#39;x&#39;

Then, the number of boys in class &#39;B&#39; = (x + 8)

So, x + x + 8 = 92

⇒ x = (92 - 8) ÷ 2 = 42

Therefore, the number of boys in classes &#39;A&#39; and &#39;B&#39; is 42 and 50  respectively

Total weight of all boys in class &#39;A&#39; = (42 × 45) = 1890 kg

Total weight of all boys in class &#39;B&#39; = (1890 + 410) = 2300 kg

So, the average weight of a boy in class &#39;B&#39; = 2300 ÷ 50 = 46 kg

 

Q:6 The correct answer is option 1 i.e. 24 years.

The sum of the present ages of Tanish, Vikesh, Dinesh, and Ashish

⇒ 24 × 4 = 96 years

The sum of the present ages of Tanish and Vikesh = (18 × 2) = 36 years

The sum of the present age of Tanish, Vikesh, and Ashish

⇒ (3 × 20) = 60 years

So, the present age of Dinesh = (96 – 60) = 36 years

The present age of Tanish = is either (36 - 12) or (36 + 12) = either 24 years or 48 years

As the sum of the ages of Tanish and Vikesh is 36 years, so the present age of Tanish is less than 36 years.

So, the present age of Tanish is 24 years

 

Q:7 The correct answer is option 3 i.e. Only A and C

Since, the new average increases by 0.5 years.

So, sum of the ages of the added students – sum of the ages of the students who left = 60 × 0.5 = 30 years

Option A:

(45 + 22 + 31) – (17 + 24 + 27) = 30 years

So, option A can be the answer.

Option B:

(64 + 22 + 31) – (17 + 24 + 44) = 32 years

So, option B cannot be the answer.

Option C:

(37 + 22 + 31) – (17 + 24 + 19) = 30 years

So, option C can be the answer.

 

Q:8 The correct answer is option 2 i.e. 61 years

Sum of the age of the members before marriage = 42 × 5 = 210 years

Sum of the age of the members after marriage = 40 × 6 = 240 years

Let, the age of the rest three members be 5x, 14x, and 15x, respectively.

Sum of the age of the rest three members = 240 – (76 + 32 + 30) = 102 years

So, 34x = 102

x = 3

Age of the youngest member = 5 × 3 = 15 years

Required difference = 76 – 15 = 61 years

 

Q:9 The correct answer is option 4 i.e. All (i), (ii), and (iii).

Total weight of the class = x × y = xy kg

According to the question,

⇒ xy + 50 = (x + 1)(y +1)

⇒ xy + 50 = xy + x + y + 1

⇒ x + y = 49

⇒ x = 49 – y ….(1)

Again, one student joins the class,

⇒ xy + 50 + 50 = (x + 2)(y + 1.5)

⇒ xy + 100 = xy + 2y + 1.5x + 3

⇒ 97 = 2y + 1.5x

Putting the value of x:

⇒ 1.5(49 – y) + 2y = 97

⇒ 73.5 – 1.5y + 2y = 97

⇒ 0.5y = 23.5

⇒ y = 47

Putting the value of y in Equation (1)

⇒ x = 49 – 47 = 2

(i) If Anant joins the class, the average weight of the class increases by 0.5 kg, find the weight of Anant.

Let the weight of Anant = a kg

According to the question,

⇒ (47 × 2 + x)/3 = 47.5

⇒ 94 + x = 142.5

⇒ x = 48.5 kg

(ii) The number of students in the class = 2

(iii) Find the value of (y – 3x)

⇒ (y – 3x) = (47 – 3 × 2) = 47 – 6 = 41

Hence, option All (i), (ii), and (iii)

 

Q:10 The correct answer is option 2 i.e.\(\frac{a b+a d}{a+c}\).

Total runs scored by a cricketer in ‘a’ matches = ab

Total runs scored by a cricketer in ‘c’ matches = cd

Total matches played = (a + c)

Total runs scored in (a + c) matches = ab + cd

Required average = \(\frac{a b+a d}{a+c}\)

So, this is it for today. We will meet again with another new topic. Till then, you can practice the questions again by downloading the PDF of Average.

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