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<html><body><h2 id="content-id-4935081267-2"><b>Quadratic Equation Questions Overview</b></h2><p>Quadratic Equation Questions have a good weightage in the Rbi Assistant Exam and the type of question asked in Rbi Assistant exam is similar to the question mentioned below. It has been solved and explained by KD Live Experts under the guidance of Neetu Mam and they have tried to elaborate the concept used in Quadratic Equation Questions.</p><h2 id="content-id-3296184507-3"><b> Comprehension On Quadratic Equation Questions</b></h2>Direction: In each of these questions, two equations (I) and (II) are given. You have to solve both equations and mark the appropriate answer.
<h2 id="content-id-8209673514-4"><b>Question On Quadratic Equation </b></h2>LCM of m and n is 99 and HCF of n and m is 3, such that m > n.

I. Roots of the equation:  x2 – mx + 162 = 0

II. Roots of the equation: y2 + (6 + n)y + 56 = 0
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 45 Seconds </h3></div></div><h2 id="content-id-7084516293-5"><b> Quadratic Equation Questions Options</b></h2><ol><li><p>I > II</p>
</li><li><p>II > I</p>
</li><li><p><span style="font-size:11pt"><span style="font-family:Calibri,sans-serif">I ≥ I I</span></span></p>
</li><li><p><span style="font-size:11pt"><span style="font-family:Calibri,sans-serif">I I ≥ I</span></span></p>
</li><li><p>I = II or relationship cannot be determined</p>
</li></ol> <h2 id="content-id-9607143582-6"><b> Quadratic Equation Questions Solution</b></h2><p>The correct answer is <strong>option 1</strong> i.e.<strong> I > II</strong>.</p>

<p>LCM × HCF = mn</p>

<p>99 × 3 = mn</p>

<p>mn = 297</p>

<p>So, the possile value of m = 33, n = 9</p>

<p>I. x<sup>2</sup> – mx + 162= 0</p>

<p>⇒ x<sup>2</sup> – 33x + 162 = 0</p>

<p>⇒ x<sup>2</sup> – 27x – 6x + 162 = 0</p>

<p>⇒ x(x – 27) – 6(x – 27) = 0</p>

<p>⇒ (x – 27) (x – 6) = 0</p>

<p>x = 27, 6</p>

<p>II. y<sup>2</sup> + (6 + n)y + 56 = 0</p>

<p>⇒ y<sup>2</sup> + (6 + 9)y + 56 = 0</p>

<p>⇒ y<sup>2</sup> + 15y + 56 = 0</p>

<p>⇒ y<sup>2</sup> + 8y + 7y + 56 = 0</p>

<p>⇒ y (y + 8) + 7(y + 8) = 0</p>

<p>⇒ (y + 8) ( y + 7) = 0</p>

<p>⇒ y = -8, -7</p>

<p>So, I > Ii</p>
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The correct answer is option 1 i.e. I >  - Quadratic Equation Questions are asked in Rbi Assistant exams and your question has been explained by experts like Neetu Mam.

 Comprehension On Quadratic Equation Questions

 Quadratic Equation Questions Tips and Tricks

LCM of m and n is 99 and - Quadratic Equation Questions for Rbi Assistant

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